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Java 8 Method Reference Evaluation

45 pointsby cnahrover 8 years ago

5 comments

pdpiover 8 years ago
It&#x27;s much easier to keep track of what&#x27;s happening if you don&#x27;t try to write it as one-liners.<p>This:<p><pre><code> final Runnable newRef = new Counter()::show; </code></pre> is the same as this:<p><pre><code> final Counter counter = new Counter(); final Runnable newRef = counter::show; </code></pre> Which is roughly equivalent to this:<p><pre><code> final Counter counter = new Counter(); final Runnable newRef = () -&gt; { counter.show(); }; </code></pre> Which is, of course, not the same thing as<p><pre><code> final Runnable newLambda = () -&gt; { new Counter().show(); }; </code></pre> The rest of the differences follow naturally from this distinction.
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Leonover 8 years ago
Something to add that would help on your examples, would be a non-static counter to the static inner class. I think that would really help convey when when multiple objects are created but the reference to the first class instance is kept. With the static count variable new object instantiation is tracked, but misses a detail on object references that is interesting.<p>Specifically for this example:<p><pre><code> System.out.println(&quot;\nVariable in method reference&quot;); obj = new Counter(); &#x2F;&#x2F; NPE if after method reference declaration! final Runnable varRef = obj::show; System.out.println(&quot;Running...&quot;); varRef.run(); obj = new Counter(); varRef.run(); </code></pre> obj::show was evaluated, so varRef should be pointing to the original instance method of show, even when called the second time. Which could potentially create a memory leak if someone is tracking the method references and recreating objects underneath unknowingly.<p>However if I am completely wrong about this please tell me! I have not gone through and run this code for confirmation, so I would be very happy to know if I&#x27;m mistaken. I&#x27;m going by memory without reference checking or testing. In either case if I am wrong or right - please put a note about this situation! It would help immensely and make your post even more interesting.<p>Thanks!<p>Leon
twicover 8 years ago
What&#x27;s correct here is that the target of a method reference is evaluated when the reference is evaluated.<p>What&#x27;s incorrect is that references to static (or other) variables are somehow treated differently. The author has misinterpreted their own code - see jwolfe&#x27;s and my comments on the post.
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mdadmover 8 years ago
Google cache since it seems to be 404&#x27;ing: <a href="http:&#x2F;&#x2F;webcache.googleusercontent.com&#x2F;search?q=cache:20xO-ms-ek8J:news.kynosarges.org&#x2F;2016&#x2F;10&#x2F;23&#x2F;java-method-reference-evaluation&#x2F;+&amp;cd=1&amp;hl=en&amp;ct=clnk&amp;gl=us" rel="nofollow">http:&#x2F;&#x2F;webcache.googleusercontent.com&#x2F;search?q=cache:20xO-ms...</a>
therealidiotover 8 years ago
404?
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