TE
TechEcho
Home24h TopNewestBestAskShowJobs
GitHubTwitter
Home

TechEcho

A tech news platform built with Next.js, providing global tech news and discussions.

GitHubTwitter

Home

HomeNewestBestAskShowJobs

Resources

HackerNews APIOriginal HackerNewsNext.js

© 2025 TechEcho. All rights reserved.

Veritasium: The SAT Question Everyone Got Wrong [video]

280 pointsby goplayoutsideover 1 year ago

28 comments

js2over 1 year ago
This is an 18 minute video about an SAT problem from 1982. If you&#x27;re not sure you want to commit to it, here&#x27;s a contemporaneous NYT article:<p><a href="https:&#x2F;&#x2F;www.nytimes.com&#x2F;1982&#x2F;05&#x2F;25&#x2F;us&#x2F;error-found-in-sat-question.html?unlocked_article_code=1.JE0.bxTM._IG_RekctyzU&amp;smid=url-share" rel="nofollow">https:&#x2F;&#x2F;www.nytimes.com&#x2F;1982&#x2F;05&#x2F;25&#x2F;us&#x2F;error-found-in-sat-que...</a><p>(Gift link.)<p>And a recent Scientific American article:<p><a href="https:&#x2F;&#x2F;www.scientificamerican.com&#x2F;article&#x2F;the-sat-problem-that-everybody-got-wrong&#x2F;" rel="nofollow">https:&#x2F;&#x2F;www.scientificamerican.com&#x2F;article&#x2F;the-sat-problem-t...</a><p>(Both of these are linked from the video description itself.)<p>I&#x27;ll bet Marilyn vos Savant wouldn&#x27;t have got this one wrong[1]. :-)<p>[1]: <a href="https:&#x2F;&#x2F;web.archive.org&#x2F;web&#x2F;20130121183432&#x2F;http:&#x2F;&#x2F;marilynvossavant.com&#x2F;game-show-problem&#x2F;" rel="nofollow">https:&#x2F;&#x2F;web.archive.org&#x2F;web&#x2F;20130121183432&#x2F;http:&#x2F;&#x2F;marilynvos...</a>
评论 #38778592 未加载
评论 #38778229 未加载
评论 #38777843 未加载
评论 #38799636 未加载
评论 #38778332 未加载
drc500freeover 1 year ago
What makes sense to me is to think about something that DOESN&#x27;T roll.<p>Suppose I start in Greenwich, walk - without rolling - down the prime meridian to the south pole, up the international date line to the north pole, and back down the prime meridian to Greenwich.<p>How many rotations do I go through? One. I get a full rotation because I&#x27;ve followed the earth&#x27;s curvature all the way around the globe once, even though I&#x27;m walking straight without rolling.<p>So the answer is &quot;how many rotations due to rolling&quot; plus &quot;one bonus rotation for passing around the curvature of the circle.&quot;
评论 #38777799 未加载
评论 #38778582 未加载
评论 #38782560 未加载
评论 #38779128 未加载
评论 #38777126 未加载
评论 #38778529 未加载
评论 #38780249 未加载
orenlindseyover 1 year ago
The guy who figured this out (who Veritasium interviewed) is crazy smart.<p>Also, a lot of kids math problems (middle school and below) are super vague. I get that they&#x27;re designed to teach a concept, but they could do it in a more exact&#x2F;precise (idk what the word is) way.
评论 #38777065 未加载
评论 #38792129 未加载
评论 #38776903 未加载
评论 #38776823 未加载
评论 #38778333 未加载
pbj1968over 1 year ago
I’m no genius, but I used to score well on such tests as a youngster. I was handed an IQ test circa ~1996 and got about two thirds through it before I found a question where none of the responses were correct. I brought it to the teacher’s attention. “There is no way you could possibly be right, this test was reviewed first!”<p>Anyway, blame it on photocopy errors or whatever, but the answers were wrong. Still mad about it.<p>I took another one ~2007 when I was looking to be a marketing person for a construction equipment rental company. This one was about 30 questions over 60 minutes. I got to question 26, which was some extraordinarily complicated question about how many cuts would it take to chop down a large board into the pieces you needed. After I wasted several minutes methodically writing this out, I realized the true test was realizing it was a time waster question one should skip. 27-30 were far simpler and then the buzzer ran out on me.
评论 #38778670 未加载
评论 #38778981 未加载
评论 #38778409 未加载
评论 #38778401 未加载
评论 #38778572 未加载
krackersover 1 year ago
This was also the infamous amc 2015 &quot;clockblock&quot; question<p><a href="https:&#x2F;&#x2F;artofproblemsolving.com&#x2F;wiki&#x2F;index.php&#x2F;2015_AMC_10A_Problems&#x2F;Problem_14" rel="nofollow">https:&#x2F;&#x2F;artofproblemsolving.com&#x2F;wiki&#x2F;index.php&#x2F;2015_AMC_10A_...</a>
评论 #38776909 未加载
chunsjover 1 year ago
Why should we take the meaning of revolution in this problem not as the contacting point to meet the circle again, but just as the pointing the same direction? I think this is the source of confusion here.<p>I&#x27;m not the native speaker of English and I might take the meaning of &quot;revolution&quot; very absurdly here. Just curious and I have to ask this. :-)
评论 #38780293 未加载
pmayrgundterover 1 year ago
None of the explanations gave me an intuition for it except the circle rolling down a straight line with the same length as its circumference.<p>A roll down the line will rotate the circle once. Coming back the same. But rolling around one corner will add half a circumference, and another half for rolling around the other. So you get 2 * 0.5 extra circumferences, and so + 1 C. Somehow that helps with the other polynomials for me too. Super cool.
评论 #38777251 未加载
评论 #38778561 未加载
评论 #38777078 未加载
评论 #38780199 未加载
评论 #38778896 未加载
评论 #38776968 未加载
评论 #38781271 未加载
jncfhnbover 1 year ago
I think the explanation is kind of messy tbh.<p>People are going to have one of two interpretations. If a coin rolls around another coin, is the distance traveled equal to the edge along the the static coin? Or is it the distance traveled by the center of the rotating coin?<p>If it’s defined by the former, the answer is 3 because the circumference is 3x as long as that of the traveling coin. If it’s defined by the latter then it’s 4 because the circumference of the base coin buffered out by the radius of the traveling coin is 4x as long that of the traveling coin.<p>I vote 3 personally
评论 #38777284 未加载
评论 #38782714 未加载
评论 #38777345 未加载
评论 #38777542 未加载
评论 #38778829 未加载
jhnclsover 1 year ago
The coin around coin problem has its own wikipedia page, although some people want to delete it:<p><a href="https:&#x2F;&#x2F;en.wikipedia.org&#x2F;wiki&#x2F;Coin_rotation_paradox" rel="nofollow">https:&#x2F;&#x2F;en.wikipedia.org&#x2F;wiki&#x2F;Coin_rotation_paradox</a>
评论 #38778544 未加载
评论 #38778009 未加载
评论 #38778268 未加载
less_lessover 1 year ago
One interesting thing that&#x27;s not in the video: there is a real application beyond the astronomy one, a scenario where you would want to roll one object around another object, and care about how many rotations it makes.<p><a href="https:&#x2F;&#x2F;en.wikipedia.org&#x2F;wiki&#x2F;Epicyclic_gearing" rel="nofollow">https:&#x2F;&#x2F;en.wikipedia.org&#x2F;wiki&#x2F;Epicyclic_gearing</a><p>These are used for car differentials, bicycle gear hubs, pencil sharpeners, and many other applications.
TarasBobover 1 year ago
The way I think about it is imagine the circle in the middle is very tiny compared to the circle that rolls.
评论 #38777694 未加载
mlcryptoover 1 year ago
The perspective from inside the circle was mind blowing. Can that be an analogy to relativity &amp; time?
评论 #38776824 未加载
medlerover 1 year ago
The application to sidereal time is where this really gets interesting. It’s far from a trivial question of semantics or a mathematical trick. It’s something astronomers have known about for ages, since the amount of time it takes for the Earth to make one rotation is different from the perspective of distant stars than from the perspective of the sun.
评论 #38777703 未加载
评论 #38778675 未加载
ecshaferover 1 year ago
My answer to this after reading the question was 1, because by definition it is one revolution. So I thought that was trick, and the answer essentially is none of the above. But there is a lot more nuance here than just that with multiple definitions of revolution versus rotations, and sidereal time is where this answer can get weird.
评论 #38778743 未加载
评论 #38790284 未加载
sillysaurusxover 1 year ago
There is an intuitive way to see why this is true.<p>Picture a circle rolling around the outside of another. Easy to picture, right? Even if it’s not clear how many times it rotates, you can still visualize it.<p>Now imagine the outer circle has to spin around the <i>inside</i> of the first circle.<p>Stack two quarters, and try to spin the top quarter around the inside of the bottom quarter.<p>You can’t do it. There’s no room. If they’re identical size, the top quarter can’t spin &quot;around&quot; the inner edge of the bottom quarter.<p>Now put a penny on top of a quarter. Spin <i>that</i> around. Not along the outside, but along the inside of the quarter. You’ll see the penny is tracing a very tight circle. There’s not much room.<p>Now put the penny next to the quarter and spin it around the outer edge of the quarter. It goes easily. Plenty of room.<p>If you do the naive calculation, you’d get the same answer for both cases. But clearly there’s a difference.<p>The difference is more apparent if you imagine the coins had little teeth, like gears. If you go around the outside, it’ll go just fine. But if you hollow out the quarter and put teeth along the inside, and try to spin the penny around in that, you’ll find that it doesn’t make anywhere close to a full rotation each time you go around.
评论 #38777628 未加载
bobby_tableover 1 year ago
The way I think of this is: If instead of having a small circle rolling around a larger one, think of a circle with ANY non-zero radius rolling around one with a zero (or really really small) radius. You’ll always end up with at least one rotation, regardless of how small the other circle is. So +1 makes sense.
评论 #38781490 未加载
elbastiover 1 year ago
Question: the outside circle is a tire made of rubber, which wears down at a known rate.<p>Which tire wears down more:<p>A tire that rolls around a circle of circumference D.<p>A tire that rolls down a flat surface, total distance D?
评论 #38777691 未加载
评论 #38777810 未加载
voodover 1 year ago
I&#x27;m surprised that only 3 people reported the error.<p>While problem is not trivial, my initial reaction was &quot;it can&#x27;t be 3, it&#x27;s too obvious&quot;. And it seems that a lot of people in the comments here do get to the right answer on their own.<p>So, why not hundreds of reports?
评论 #38779189 未加载
评论 #38779204 未加载
scotty79over 1 year ago
Second part of the video is way more interesting, where he discusses how this toy problem actually relates to how we define what a year is depending on whether we look at the stars or at what&#x27;s on Earth.
gumbyover 1 year ago
Interesting: I took the SAT in 1982 and don’t remember this problem. They don’t give you your % right, just percentile and a mysterious score between 200 and 800 for some reason. Does 800 mean 100%?
评论 #38779281 未加载
评论 #38778898 未加载
评论 #38778398 未加载
ad404b8a372f2b9over 1 year ago
It&#x27;s odd to me that anyone would come up with 3, to me it was immediately very apparent from the diagram that the closest answer was 9&#x2F;2.
评论 #38778716 未加载
freediverover 1 year ago
Explaination that works for me is that if you were rolling it around a spot (zero diameter) you would need one full revolution.
belltacoover 1 year ago
I did a eyeball ball park estimate and figured the closest answer was 9&#x2F;2 and was right.
评论 #38780155 未加载
elwellover 1 year ago
What if the large circle rotates at the same rate that the small circle &#x27;orbits&#x27; it?
xorcistover 1 year ago
Does the video spoil the solution too or is it only the question?
评论 #38777290 未加载
评论 #38778703 未加载
stormdennisover 1 year ago
I don&#x27;t revolve once every 24 hrs, the earth does.
tim333over 1 year ago
Tldr it was a four choice multi choice question but the all the options were wrong because the people setting the test got it wrong.<p>So I&#x27;m not sure everyone got it wrong, just that they weren&#x27;t confident enough in a rushed test to cross out A,B,C and D and write in the correct answer!
lostmsuover 1 year ago
The title sort of spoils it as it becomes obvious you need to look for some issue with the trivial number solution.
评论 #38776708 未加载