I'm having some trouble understanding the article's formula; and honestly it's a little weird to see people complain about how trivial the proof is.<p>Both this article and the article it quotes introduce the "((∃ x. P(x)) → Q) ⇔ (∀ x. (P(x) → Q))" formula with absolutely no additional explanation. I guess that's fine if the article are <i>meant</i> for people with a mathematics background, but at someone who has always struggled with post-high-school-maths... what the hell?<p>I understand what ∃, ∀, ⇔, and → represent ("there exists", "for all", "equivalent" and "implies", respectively), but I have no idea how to parse the entire formula. What are P and Q?<p>After multiple tries, I'm reading it as "saying that 'there exists a x such that P(x) is true' implies Q" being equivalent to "for all x, P(x) implies Q", with the idea that P and Q are arbitrary proposals or whatever the proper terms are... But still, just processing the logical reasoning in my head is tough.<p>On the other hand "some types implement traits, and if a function expects a trait impl you can only pass it types that implement that trait" feels absolutely clear to me. It might be that Rust is good at breaking down math concepts into the essentials you need for programming. Or it might be that formal Math notation is not for me.