Maybe someone could clarify something for me here:<p>o(n) seems like a stronger statement to me than O(n), since all o(n) algorithms are O(n), but the reverse is not true.<p>Also if o(n) applies to all n, however small, whereas O(n) applies only when n -> inf,<p>(From the Wikipedia page example: 2n = O(n) but 2n != o(n))<p>Then doesn’t that means this algorithm should be applicable to even small n’s? Then it would be the opposite of a galactic algorithm, as someone above suggested, wouldn’t it?<p>Or am I missing something?