Can someone figure out a formula for this?

1 点作者 gamebak超过 11 年前

Hey guys, I've been thinking for a formula but i wasn't able to figure out. Maybe someone smarter could give me a hand.The series: b, e, g, i, k, n, p, y, 10, 12, 14, 16, 18, 1a, 1c, 1e, 1g, 1i, 1u, 1w, 1z, 21, 23, 2b, 2e, 2g, 2i, 2k, 2m, 2o, 2r, 2t, 2v, 2x, 30, 34, 37, 39, 3c, 3e, 3g, 3i, 3m , 3o, 3q, 3s, 3v , 3y, 40, 42, 44 , 46, 48, 4a, 4d, 4g, 4n, 51, 5n, 5p, 5s, 5u, 5x, 60, 62, 64, 66, 68, 6b, 6j, 6n, 6p, 6r, 6t, 6w, 71, ...Thanks for your help!

2 条评论

ColinWright超过 11 年前

I suspect here:<pre><code> ... 48, 4a, 4d, 4g‏, 4n, 51, 5n, 5p, ... </code></pre> you mean:<pre><code> ... 48, 4a, 4d, 4g, 4n, 51, 5n, 5p, ... </code></pre> If you would care to be more accurate in your question then people might take more of an interest.Also, would you care to provide some context? Is this in base 36? Are they semi-base64? What have you tried so far? What do you mean by "a formula"? What is your purpose?In short, perhaps you could be a little clearer.

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nummy超过 11 年前

format C:\