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Cylinders in Spheres

118 点作者 stansmith将近 11 年前

15 条评论

carlob将近 11 年前
One of those cases where using integrals rather than geometry is much simpler.<p><pre><code> \pi \int_-3^3 (R^2 - x^2) dx = \pi (6 R^2 - 18) </code></pre> is the volume of the rotational solid without removing the cylinder. While the volume of the cylinder is given by:<p><pre><code> \pi \int_-3^3 (R^2 - 3^2) dx = \pi 6 (R^2 - 9) </code></pre> As you can see the difference between the two volumes is 36 \pi.<p>You can actually show the solution does not depend on \pi without evaluating the integral, and then compute the &#x27;cheat&#x27; case, which would not be a cheat once you&#x27;ve made this observation.
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svantana将近 11 年前
Nice, I especially appreciate the &quot;cheat answer&quot; to the Gardner Puzzle at the bottom of the page. I have found that kind of meta-reasoning about questions quite useful, on exams and in games like Trivial Pursuit, for example.
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scotty79将近 11 年前
I once encountered question that had cheat answer. It was about trapezoid and it seemed that it had some data missing.<p>I was amazed that just assuming that the question had one answer allowed to reduce the problem to trivially calculable one by consistently manipulating the variables that were not given.<p>I was also pretty proud of myself for finding this solution.
drcode将近 11 年前
In the early eighties there was a TV show on German network television and I remember them presenting this puzzle, and I figured out the &quot;cheat solution&quot; as a kid.<p>It was this awesome TV game show that consisted entirely of Martin Gardner-style puzzles and other fiendish physics&#x2F;biology puzzles, and contestants who were all scientists. Does anyone by any chance remember the name of this German TV show? I would really like to look up more information about it! It deserves to be remembered.
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chton将近 11 年前
The cheat is absolutely brilliant reasoning.
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eps将近 11 年前
There is a simpler puzzle that&#x27;s similar to Gardner&#x27;s, but as unintuitive.<p>Take an orange and wrap a string around its diameter. Now extend the string by 1 inch and redistribute it around the orange so that it floats an even distance from it. Do the same with the Earth, i.e. wrap, extend by 1 inch and even out into a circle. The gap betwen the string and the orange&#x2F;Earth - which one is bigger?
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davtbaum将近 11 年前
It wasn&#x27;t (initially) clear to me that the cylindrical hole must enter and exit the sphere.<p>With that knowledge the solution seems pretty intuitive.
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tempestn将近 11 年前
I&#x27;m just pleased that I finally found a math puzzle on HN that I was able to solve without looking ahead! (Although I called the radius of the cylinder r&#x2F;a, where r is the radius of the sphere, which ended up making my math a bit messy...)<p>Regardless, deserves an upvote just for the cheat answer at the end. I like that kind of reasoning!
jbaskette将近 11 年前
I remember reading and solving this the problem as the end of the article (“A six inch high cylindrical hole is drilled through the center of a sphere. How much volume is left in the sphere?”) as a kid. I did it the hard way using the formula&#x27;s, but the whole point of the puzzle was what this article called the &quot;cheat&quot; answer. It reduces the solution to utter simplicity by application of some elegant logic. It&#x27;s not something of a cheat -- it&#x27;s the whole point of the puzzle.<p>I really was a kid. I was taken in by Gardner&#x27;s April 1st column that claimed among other things that a proven solution for &quot;Chess&quot; indicated that white would always win and that the opening move was P-KR4 (h4 in modern notation).
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cousin_it将近 11 年前
I solved the puzzle in my head before getting to the second paragraph in the article. Here&#x27;s the reasoning:<p>1) The area of a circle has a fixed ratio to the area of a square inscribed in that circle.<p>2) Therefore the volume of a cylinder has a fixed ratio to the volume of a square box of the same height, which sits inside that cylinder.<p>3) Therefore the biggest cylinder corresponds to the biggest box that can fit inside the sphere.<p>4) That box is obviously a cube, because what else could it be?<p>5) If a cube is inscribed in a unit sphere centered at the origin, the corners have coordinates ±1&#x2F;√3, ±1&#x2F;√3, ±1&#x2F;√3.<p>6) Now you can calculate the volume of the cylinder in your head. Do it!
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throwaway283719将近 11 年前
It reminds me of two other neat problems -<p>1. Imagine a band stretched taught around the diameter of the earth (which, for the purposes of this question, is a smooth sphere). Now imagine that the band is raised one metre from the ground at every single point along its length. How much longer is it?<p>2. Imagine perfectly parallel lines painted on the floor, exactly one foot apart, and a rigid needle of length one foot. If you throw the needle to the floor at random, what is the probability that it crosses one of the lines? (This one has a nice &#x27;cheat&#x27; solution just like the OP article).
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hammock将近 11 年前
The author never pays off the answer to the initial question- is it a fat cylinder or a skinny one? We know it has height ~1.15R (where R is sphere&#x27;s radius), but this is not easy to visualize.
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quarterwave将近 11 年前
To estimate an answer for the first problem: consider two cylinders with zero volume, the one equatorial (r=R) and the other polar (r=0). Both correspond to zero volume. Hence the maximum volume occurs (hand wave) for a height somewhere between 0 and 2R. Not knowing better, the initial estimate for h is to bisect this interval, to give h_est = R (compare 1 with 2&#x2F;sqrt(3) ~= 1.15).<p>It would be nice to construct a first order correction term. Any ideas?
drjoe047将近 11 年前
Regarding the Napkin Ring part of the problem.<p>Had the author simplified the formula for &quot;Vanswer&quot; rather than plugging in values for h &amp; c, he would have gotten:<p>Vanswer = (Pi&#x2F;6) * h^3<p>From which is it easy to see that the answer in this particular case is 36 * Pi but it also makes clear that the answer does not depend on R.
e3pi将近 11 年前
...and its Archimedean inverse(his favorite!): a Wilson(tm)* soccer ball enjoys 2&#x2F;3 the volume and 2&#x2F;3 the surface content of its minimal cylindrical official Wilson(tm) shipping clear plastic blister pack.<p>*citation: Tom Hanks in &quot;Castaway&quot;